Tag:

leap year

C#Programs

How to check if a year is a leap year in C

written by programmerdude

In this example we show you how to check if a year is a leap year in C

To determine whether a year is a leap year, follow these steps:

If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
The year is a leap year (it has 366 days).
The year is not a leap year (it has 365 days).

Example

#include <stdio.h>

int main() 
{
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   // is leap year if divisible by 400
   if (year % 400 == 0) 
   {
      printf("%d is a leap year.", year);
   }
   // not leap year if divisible by 100 but not by 400
   else if (year % 100 == 0) 
   {
      printf("%d is not a leap year.", year);
   }
   // is leap year if not divisible by 100 but by 4
   else if (year % 4 == 0) 
   {
      printf("%d is a leap year.", year);
   }
   // not leap years
   else 
   {
      printf("%d is not a leap year.", year);
   }

   return 0;
}

Here are a few test runs

Enter a year: 2000
2000 is a leap year.

Enter a year: 2002
2002 is not a leap year.

Enter a year: 2004
2004 is a leap year.

18th April 2022 0 comment

Check if a Year is a Leap Year in Java

written by programmerdude

In this example we will look at how to check if a year is a leap year or not

if a year is not divisible by 4 then it is not a leap year
if the year is not divisible by 100 then it is a leap year
if the year is not divisible by 400 then it is not a leap year
Otherwise it is a leap year

Example

import java.util.Scanner;

public class JavaApplication1 
{
    private static Scanner myScanner;
    public static void main(String[] args) 
    {
        
        int year;
        // get user input
        myScanner= new Scanner(System.in);
        year = myScanner.nextInt();
 
        // condition check
        if ((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))) 
        {        
            // true- Print leap year
            System.out.println(year + " : Leap Year");
        }
        else 
        {
            // false- Print Non-leap year
            System.out.println(year + " : Non - Leap Year");
        }
    }
}

Here are a few test runs

run:
2000
2000 : Leap Year

run:
2002
2002 : Non - Leap Year

run:
2004
2004 : Leap Year

17th April 2022 0 comment

Programs

How to Check if its a Leap Year in JavaScript

written by programmerdude

In this example we check if a year is a leap year

Some examples use a formula to check if a year is a leap year, this example checks if the month of February contains 29 days in the year specified

Example 1

// program to check leap year
function checkLeapYear(year) 
{

    const leap = new Date(year, 1, 29).getDate() === 29;
    if (leap) 
	{
        console.log(year + ' is a leap year');
    } 
	else 
	{
        console.log(year + ' is not a leap year');
    }
}

// remove comment to take input
// const year = prompt('Enter a year:');
checkLeapYear(2000);
checkLeapYear(2002);
checkLeapYear(2004);

When you run this you will see something like this

2000 is a leap year
2002 is not a leap year
2004 is a leap year

You can remove the comment to take user input like this

// program to check leap year
function checkLeapYear(year) 
{

    const leap = new Date(year, 1, 29).getDate() === 29;
    if (leap) 
	{
        console.log(year + ' is a leap year');
    } 
	else 
	{
        console.log(year + ' is not a leap year');
    }
}

// remove comment to take input
const year = prompt('Enter a year:');
checkLeapYear(year);

13th April 2022 0 comment

Programs

How to check whether a year is a leap year or not in C#

written by programmerdude

In this example we will show to check if a year is a leap year in C#

There is a basic formula for this

To determine whether a year is a leap year, follow these steps:

If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
The year is a leap year (it has 366 days).
The year is not a leap year (it has 365 days).

Example

using System;

namespace ConsoleApp1
{
    class Program
    {
        static void Main(string[] args)
        {
            int myYear;
            Console.Write("Input an year : ");
            myYear = Convert.ToInt32(Console.ReadLine());

            if ((myYear % 400) == 0)
                Console.WriteLine("{0} is a leap year.\n", myYear);
            else if ((myYear % 100) == 0)
                Console.WriteLine("{0} is not a leap year.\n", myYear);
            else if ((myYear % 4) == 0)
                Console.WriteLine("{0} is a leap year.\n", myYear);
            else
                Console.WriteLine("{0} is not a leap year.\n", myYear);
            Console.ReadLine();
        }
    }
}

Here are a couple of test runs

Input an year : 1992
1992 is a leap year.

Input an year : 2000
2000 is a leap year.

Input an year : 2022
2022 is not a leap year.

12th April 2022 0 comment