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In this example we show you how to check if a year is a leap year in C

To determine whether a year is a leap year, follow these steps:

- If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.
- If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.
- If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.
- The year is a leap year (it has 366 days).
- The year is not a leap year (it has 365 days).

### Example

#include <stdio.h> int main() { int year; printf("Enter a year: "); scanf("%d", &year); // is leap year if divisible by 400 if (year % 400 == 0) { printf("%d is a leap year.", year); } // not leap year if divisible by 100 but not by 400 else if (year % 100 == 0) { printf("%d is not a leap year.", year); } // is leap year if not divisible by 100 but by 4 else if (year % 4 == 0) { printf("%d is a leap year.", year); } // not leap years else { printf("%d is not a leap year.", year); } return 0; }

Here are a few test runs

Enter a year: 2000 2000 is a leap year. Enter a year: 2002 2002 is not a leap year. Enter a year: 2004 2004 is a leap year.